MHB Finding the Equation of a Line with Given Slope and Y-Intercept

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The equation of the line with a slope of 14 and a y-intercept of 0 is y = 14x. This line indeed passes through the origin, as all lines of the form y = mx do. For any value of x, the corresponding point on the line can be calculated using the equation. Specifically, when x equals 0, the point is (0,0), confirming it goes through the origin. This reinforces the understanding of linear equations in slope-intercept form.
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Given slope = 14; y-intercept is 0, find the equation of the line.

Solution:

y = mx + b

y = 14x + 0

y = 14x

The equation of the line is y = 14x.

Correct?
 
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Of course it is!
 
Does the line y = 14x go through the origin?
 
RTCNTC said:
Does the line y = 14x go through the origin?

All lines of the form $y=mx$ go through the origin...for any $x=a$, the point $(a,ma)$ is on the line...what point do we get if $a=0$?
 
Good information for my notes.
 
Thread 'Erroneously finding discrepancy in transpose rule'

Thread 'Erroneously finding discrepancy in transpose rule'

Obviously, there is something elementary I am missing here. To form the transpose of a matrix, one exchanges rows and columns, so the transpose of a scalar, considered as (or isomorphic to) a one-entry matrix, should stay the same, including if the scalar is a complex number. On the other hand, in the isomorphism between the complex plane and the real plane, a complex number a+bi corresponds to a matrix in the real plane; taking the transpose we get which then corresponds to a-bi...
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