Finding the focal length of a negative lens without another lens.

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SUMMARY

The discussion focuses on determining the focal length of a negative lens using geometric principles rather than complex formulas. Participants emphasize that the linear magnification formula and the lens equation are not necessary for this problem. Instead, the key insight is that by extending the divergent rays from the lens, one can identify the focal point where these rays converge. This method simplifies the process of finding the focal length of a negative lens.

PREREQUISITES
  • Understanding of linear magnification formula
  • Familiarity with lens equations
  • Basic principles of optics, specifically divergent lenses
  • Knowledge of geometric constructions related to light rays
NEXT STEPS
  • Study the properties of divergent lenses and their image formation
  • Learn about geometric optics and ray diagrams
  • Explore the derivation and application of the lens equation
  • Investigate practical experiments to measure focal lengths of various lenses
USEFUL FOR

Students studying optics, physics educators, and anyone interested in practical applications of lens properties and image formation techniques.

kPepis
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Homework Statement


A simple method for determining the focal length of a negative lens is shown below. Prove this is true.
Negativelensfocallenght.png

Homework Equations


linmag.gif

The Attempt at a Solution


The linear magnification formula relates magnification, the distance from the lens to the image (i), the distance from the lens to the object (o) and the height of the two images (h'/h). The lens equation relates distance to the object and distance to the image and the focal length. I know I have to use these two equations but I have not been able to prove this is true. This is kind of frustating considering it's a simple problem, but can anyone point me in the right direction?
 
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I don't think you have to use the formulas above. What you have on the screen is not the image of any object.
What kind of image will be produced by a divergent lens? Can you catch on a screen? Where will be the image of the sun produced by the lens?

But the problem it is much simpler. Is pure geometry. If you extend the divergent rays (the ones on the left hand side of the lens) to the right hand side of the lens, they will meet in a point. What is the location of this point? How far from the lens?
 

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