Finding the Height of a Circular Roller in a Symmetric Worm Thread

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Homework Help Overview

The problem involves determining the height that the top of a circular roller rises above the top of a symmetric worm thread, given a machine tool diagram with specific dimensions and relationships. The roller has a diameter of 1.5 inches, and participants are asked to find the value of d based on the provided information.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need for clearer images and labeled variables to facilitate understanding. There are attempts to express the relationship between the roller's radius, height, and other dimensions in terms of known variables. Some participants question the assumptions made regarding the geometry of the problem, particularly the relationships between the roller, the thread, and the dimensions involved.

Discussion Status

The discussion is ongoing, with participants providing suggestions for clearer communication and exploring different interpretations of the problem setup. There are multiple values for d being discussed, and some participants are attempting to reconcile their calculations with those found in a reference book. Guidance has been offered regarding the need for readable equations and diagrams.

Contextual Notes

There are constraints related to the clarity of images and the presentation of equations, which may be impacting the ability to effectively communicate the problem and its solution. Participants are encouraged to utilize available tools for better presentation of mathematical expressions.

Epsilon645
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Homework Statement


The machine tool diagram on the right shows a symmetric worm
thread, in which a circular roller of diameter 1.5 inches sits.
Find the amount d that the top of the roller rises above the
top of the thread, given the information in the diagram. (Hint:
Extend the slanted sides of the thread until they meet at a point.)

454418e1-500a-407d-9ca6-05a7426cac0a.jpeg

Homework Equations

The Attempt at a Solution


CamScanner-New Document 32-g10600W00r20P20y40Y40d10-001.jpg

WP_20170306_001.jpg
 
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Unreadable and sizeways images? You have to be kidding. My suggestion would be to post a single readable image with the picture and labeled variables, such as ##\alpha##, ##d##, ##r##, and possibly others. Then write (type!) your solution in terms of known variables. So you get ##d = \text{ some formula}##. Only put in the values at the end. Then your solution would be readable and understandable.
[Edit, added]: Here's a picture:
picture.jpg

Now, you know ##r,~a,~\theta##. Solve for ##d## in terms of them.
 
Last edited:
So we have r = 0.75, h = 3.1722 and w = 2.7990. In the end it will be r - d = h - w which would be d = 0.3768. I looked at the back of the book the answer is 0.476. And the reason is because r does not make a right triangle with w as its leg. There is a slight space with the circle and the symmetric thread. Look at the picture below:
WP.jpg
 
LCKurtz said:
Unreadable and sizeways images? You have to be kidding. My suggestion would be to post a single readable image with the picture and labeled variables, such as ##\alpha##, ##d##, ##r##, and possibly others. Then write (type!) your solution in terms of known variables. So you get ##d = \text{ some formula}##. Only put in the values at the end. Then your solution would be readable and understandable.
[Edit, added]: Here's a picture:
View attachment 114142
Now, you know ##r,~a,~\theta##. Solve for ##d## in terms of them.

Epsilon645 said:
So we have r = 0.75, h = 3.1722 and w = 2.7990. In the end it will be r - d = h - w which would be d = 0.3768. I looked at the back of the book the answer is 0.476. And the reason is because r does not make a right triangle with w as its leg. There is a slight space with the circle and the symmetric thread.

Again, your image is impossible to read. And, yes, ##r## is perpendicular to its leg. You haven't shown readable equations (type them in here, don't post images) for ##h## and ##w## so I don't know what you are doing wrong. It doesn't help when you just post numbers. Using my figure, you should get ##w = 2.897## and ##h = 3.172##. This will get you ##d=.4755##.
[Edit, added:] I think I see where you may be going wrong. Notice that ##w## is the hypotenuse of the right triangle and use that.
 
Last edited:
Epsilon, I have locked this thread. Please start a new thread with an image that can be read, and with equations typed in as text, as LCKurtz asks. It's possible to use features available at this site to enter each equation you show. Look under INFO in the menu bar across the top of the screen, in the Help/How-to submenu. There's a tutorial on LaTeX (https://www.physicsforums.com/help/latexhelp/), that can be used to write just about any mathematical equation.

Also, please label the points in your drawing for ease of reference.
 
Last edited:

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