Finding the kinetic energy of an electron

bear421
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Homework Statement



This is a basic photoelectric type question.

What wavelength of light is necessary to produce photo-electrons of speed 2 * 10^6 m/s with a magnesium target?

Homework Equations



KE = pf - phi

phi = 3.7 eV
h = 6.63 * 10 ^-34

The Attempt at a Solution



I don't know how to find the energy of an electron from the velocity. Once I have that I think I can figure it out
 
Last edited:
on Phys.org
I think I figured it out! E = .5 * m * v^2
 
Your equations are right =]
 

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