Finding the Locus of a Moving Point: Solving for a Hyperbola Using Dot Products

Click For Summary
SUMMARY

The discussion centers on finding the locus of a moving point P in relation to points A(a, 0), A'(-a, 0), B(b, 0), and B'(-b, 0) using the equation AP.PA' = BP.PB'. The calculations reveal that the locus of P is a hyperbola, with the asymptotes determined to be y = ±x. The confusion arose from interpreting the terms AP, PA', BP, and PB' as scalar distances rather than vectors, which clarified the calculations and led to the correct identification of the asymptotes.

PREREQUISITES
  • Understanding of hyperbolas and their properties
  • Familiarity with vector operations, specifically dot products
  • Knowledge of coordinate geometry and distance formulas
  • Ability to manipulate algebraic expressions and equations
NEXT STEPS
  • Study the properties of hyperbolas in coordinate geometry
  • Learn about vector operations and their applications in physics and mathematics
  • Explore the derivation of asymptotes for conic sections
  • Practice solving problems involving distances and loci in a Cartesian plane
USEFUL FOR

Students studying advanced mathematics, particularly those focusing on conic sections, vector calculus, and coordinate geometry. This discussion is beneficial for anyone looking to deepen their understanding of hyperbolas and their applications.

Appleton
Messages
91
Reaction score
0

Homework Statement



A point P moves so that its distances from A(a, 0), A'(-a, 0), B(b, 0) B'(-b, 0) are related by the equation AP.PA'=BP.PB'. Show that the locus of P is a hyperbola and find the equations of its asymptotes.

Homework Equations

The Attempt at a Solution



AP.PA' = ((a-x)\boldsymbol i + y\boldsymbol j).((-a-x)\boldsymbol i+y\boldsymbol j)
AP.PA' = x^2-a^2+y^2
BP.PB' = ((b-x)\boldsymbol i + y\boldsymbol j).((-b-x)\boldsymbol i+y\boldsymbol j)
BP.PB'= x^2-b^2+y^2

So

a^2=b^2

This result sugests that their is no constraint on P. This is not consistent with the question.
 
Last edited:
Physics news on Phys.org
Appleton said:
AP.PA' = ((a-x)\boldsymbol i + y\boldsymbol j).((-a-x)\boldsymbol i+y\boldsymbol j)
AP.PA' = x^2-a^2+y^2
BP.PB' = ((b-x)\boldsymbol i + y\boldsymbol j).((-b-x)\boldsymbol i+y\boldsymbol j)
BP.PB'= x^2-b^2+y^2
The second line does not follow from the first line and the fourth does not follow from the third.
Write out the intermediate steps between the first and second lines and you will see what went wrong.
 
Thanks for your reply andrewkirk. Unfortunately I'm still not able to identify my error. Here are the steps I omitted:

AP.PA' = ((a-x)\boldsymbol i + y\boldsymbol j).((-a-x)\boldsymbol i+y\boldsymbol j)

The dot product is distributive over vector addition, so

AP.PA' = (a-x)\boldsymbol i.(-a-x)\boldsymbol i+ y\boldsymbol j.(-a-x)\boldsymbol i+(a-x)\boldsymbol i.y\boldsymbol j+y\boldsymbol j.y\boldsymbol j

\boldsymbol i.\boldsymbol i=\boldsymbol j.\boldsymbol j=1 and \boldsymbol i.\boldsymbol j= 0

so
AP.PA' = x^2-a^2+y^2

Alternatively this shorthand is suggested by my book;

if
\boldsymbol a = x_1\boldsymbol i+ y_1\boldsymbol j

and
\boldsymbol b = x_2\boldsymbol i+ y_2\boldsymbol j

then
\boldsymbol a.\boldsymbol b=x_1x_2+y_1y_2

so
((a-x)\boldsymbol i + y\boldsymbol j).((-a-x)\boldsymbol i+y\boldsymbol j) =(a-x)(-a-x)+y^2

= -a^2+x^2+y^2
 
Actually you're quite correct. My mistake. I can't see any error in your calculations.

However, I have another idea. The question refers to the distances of P from the four points, not to the displacement vectors. If they are being careful with their words then the items AP, PA', BP, PB' are to be interpreted as scalar amounts, not vectors, and the dot between them is to be interpreted as simple multiplication (not a dot product).

I suggest trying what happens when you make that interpretation.
 
Thanks for that, it makes sense now, so the asymptotes must be y =+-x
 

Similar threads

  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K