Finding the magnitude of acceleration

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To find the magnitude of the toy train's acceleration after one wheel sticks, first calculate the distance traveled while it rolls at a steady speed for 2.04 seconds. This distance can be determined using the initial speed of 1.86 m/s. After finding the total distance traveled before the wheel sticks, subtract this from the total distance of 5.06 m to determine the distance covered while decelerating. With the initial and final velocities known, apply a kinematic equation to solve for acceleration. The key is to use the correct kinematic formula to find the acceleration during the deceleration phase.
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Homework Statement



A toy train is pushed forward and released at x0=1.42 m with a speed of 1.86 m/s. It rolls at a steady speed for 2.04 s, then one wheel begins to stick. The train comes to a stop 5.06 m from the point at which it was released. What is the magnitude of the train’s acceleration after its wheel begins to stick?

Homework Equations



I can't figure out the equation or how to start this problem?

The Attempt at a Solution

 
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Draw a picture, and remember that when the toy is released the toy has constant velocity until its wheel gets stuck. So calculate the distance traveled in that time.

Once you have that you can subtract all the distances to get the distance traveled when under a negative acceleration due to the sticky wheel. You will have distance travelled, initial velocity, and final velocity. Then you can solve for the 'a' using a well-chosen kinematic equation.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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