Finding the magnitude of the magnetic field of a moving point charge

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SUMMARY

The discussion centers on calculating the magnetic field produced by a moving point charge traveling at a speed of 2 x 107 m/s along the x-axis. The magnetic field at a point located at x=4m is evaluated using the equation vec{B} = \frac{\mu_o}{4\pi}q\frac{\vec{v}\times \vec{r}}{r^2}. The participants conclude that since the charge's path and the evaluation point are collinear, the cross product v x r equals zero, resulting in a magnetic field of zero at that location. They also suggest that if the charge were moving along a different axis, the magnetic field would vary over time due to changes in the cross product and distance.

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OmegaFury
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Question: A point charge is moving with speed 2 x 107m/s along the x axis. At t=0, the charge is at x= 0m and the magnitude of the field at x=4m is B0. The magnitude of the magnetic field at x= 4m when t= 0.1μs is:The equation and my attempt at solving it is in the attachment.
--I also converted amperes to 1C/1s and I figured that theta is 90 degrees and the magnitude of the unit vector r is one, and thus the cross product of vector v and unit vector r is 2 x 10^7 m/s. ( 2 x 10^7 times one times sin(90 degrees).
 

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OmegaFury said:
Question: A point charge is moving with speed 2 x 107m/s along the x axis. At t=0, the charge is at x= 0m and the magnitude of the field at x=4m is B0. The magnitude of the magnetic field at x= 4m when t= 0.1μs is:


The equation and my attempt at solving it is in the attachment.
--I also converted amperes to 1C/1s and I figured that theta is 90 degrees and the magnitude of the unit vector r is one, and thus the cross product of vector v and unit vector r is 2 x 10^7 m/s. ( 2 x 10^7 times one times sin(90 degrees).

Your equation for the magnetic field at a location given by vector r from the moving point charge is:
$$\vec{B} = \frac{\mu_o}{4\pi}q\frac{\vec{v}\times \vec{r}}{r^2}$$
You weren't given a value for the point charge q (so your use of the elementary charge is not warranted).

The problem seems to indicate that the "test location" where the field is to be evaluated is directly along the path of the moving charge (the charge is moving along the x-axis, the test location is at x=4m and no y-offset is given). What should that tell you about the results of the cross product v x r ?
 
gneill said:
The problem seems to indicate that the "test location" where the field is to be evaluated is directly along the path of the moving charge (the charge is moving along the x-axis, the test location is at x=4m and no y-offset is given).What should that tell you about the results of the cross product v x r ?

That would make the cross product zero, wouldn't it? But that would make the magnetic field zero. If that's true, why would it change when t= 0.1 microseconds?
 
OmegaFury said:
That would make the cross product zero, wouldn't it? But that would make the magnetic field zero. If that's true, why would it change when t= 0.1 microseconds?

Good question :smile: It wouldn't change. Is the problem statement exactly as you've given it?
 
Exactly as given. It should be 0 though at any given time if vector v is on the same axis as vector r. Thanks for pointing that out. There might be a typo in the problem or something. If, perhaps, the field point was on a different axis or the charge was moving along a different axis, then the magnetic field would change over time because the cross product wouldn't be 0, and the distance r to the field point would be changing with time.
 
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OmegaFury said:
Exactly as given. It should be 0 though at any given time if vector v is on the same axis as vector r. Thanks for pointing that out. There might be a typo in the problem or something. If, perhaps, the field point was on a different axis or the charge was moving along a different axis, then the magnetic field would change over time because the cross product wouldn't be 0, and the distance r to the field point would be changing with time.

Yup. That's my take on it too.
 

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