A 4.27-kg object is thrown vertically upward from the surface of Mercury, where the acceleration due to gravity is g1 = 3.70 m/s2. The initial velocity is v1, and the object reaches a maximum height of y1. What is the maximum height, y2, if the object is thrown with a speed of v2 = 1.99v1 from the surface of Saturn\'s moon Iapetus? The acceleration due to gravity on Iapetus is g2 = 0.223 m/s2. Give your answer as a multiple of y1.
Vf2- Vi2 = 2a∆y
The Attempt at a Solution