Finding the maximum height given multiple variables

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SUMMARY

The maximum height of an object thrown vertically from the surface of Saturn's moon Iapetus, with an initial speed of v2 = 1.99v1, is calculated to be y2 = 29.30 y1, where y1 is the maximum height achieved from Mercury. The gravitational acceleration on Mercury is g1 = 3.70 m/s², while on Iapetus it is g2 = 0.223 m/s². The kinematic equation used for this calculation is Vf² - Vi² = 2a∆y, which relates the final and initial velocities to the acceleration and displacement.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of gravitational acceleration values on different celestial bodies
  • Ability to manipulate algebraic expressions
  • Familiarity with the concept of maximum height in projectile motion
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  • Study the application of kinematic equations in different gravitational fields
  • Explore the effects of varying initial velocities on maximum height
  • Research gravitational acceleration on other celestial bodies
  • Learn about projectile motion and its equations in detail
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kaitwhit
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Homework Statement



A 4.27-kg object is thrown vertically upward from the surface of Mercury, where the acceleration due to gravity is g1 = 3.70 m/s2. The initial velocity is v1, and the object reaches a maximum height of y1. What is the maximum height, y2, if the object is thrown with a speed of v2 = 1.99v1 from the surface of Saturn\'s moon Iapetus? The acceleration due to gravity on Iapetus is g2 = 0.223 m/s2. Give your answer as a multiple of y1.


Homework Equations


Vf2- Vi2 = 2a∆y


The Attempt at a Solution


y2=29.30 y1
 
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kaitwhit said:

Homework Statement



A 4.27-kg object is thrown vertically upward from the surface of Mercury, where the acceleration due to gravity is g1 = 3.70 m/s2. The initial velocity is v1, and the object reaches a maximum height of y1. What is the maximum height, y2, if the object is thrown with a speed of v2 = 1.99v1 from the surface of Saturn\'s moon Iapetus? The acceleration due to gravity on Iapetus is g2 = 0.223 m/s2. Give your answer as a multiple of y1.


Homework Equations


Vf2- Vi2 = 2a∆y


The Attempt at a Solution


y2=29.30 y1
Hi kaitwhit, Welcome to Physics Forums.

Try using the x2 and x2 buttons on the edit panel header to create superscripts and subscripts in your equations :wink:

Can you show the work you did to arrive at your result so that we can know how to help?
 

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