Finding the Normal Line for a Curve at a Given Point

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Homework Help Overview

The discussion revolves around finding the equation of the normal line to the curve y = -3x² at a specific point, (-1, -3). The subject area involves calculus, specifically the use of derivatives to analyze the properties of curves.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the slopes of perpendicular lines and how to derive the slope of the normal line from the tangent line's slope. There is an emphasis on using calculus to find these slopes.

Discussion Status

Some participants have provided guidance on the relationship between the slopes and how to approach finding the normal line. The original poster expresses understanding after receiving clarification.

Contextual Notes

The original poster explicitly states they are not looking for the tangent line's equation, indicating a focus on the normal line instead. There is an assumption that the necessary calculus concepts are understood by the participants involved.

fatima_a
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find the equation of the normal line to the curve y = -3x^2 at the point (-1,-3).


you have to use derivatives.


i am not asking for the equation of the tangent line i know that is 6x + 3. please show all the steps.

the answer is y = -1/6x - 19/6
 
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Do you know the relationship between the gradient of two perpendicular lines?
 
Another term for gradient in this context is "slope." You can use calculus to find the slope of the tangent line. What is the slope of the line perpendicular to the tangent line? That will be the slope of the line you want. You know a point on this line, so you will have all the information you need to get the equation of this second line.
 
thanks i got it
 

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