Equation of Circle Passing Through Given Point and Line with Given Radius

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Homework Help Overview

The problem involves finding the equation of a circle that passes through the point A(-3,1) with a specified radius of 2, while the center of the circle lies on the line defined by the equation 2x-3y+3=0.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the distance from point A to the center of the circle and the given radius. There are suggestions to use the radius in conjunction with the equations derived from the circle's properties. Some participants question the clarity of the problem setup and explore different methods for expressing the center's coordinates.

Discussion Status

The discussion is ongoing, with participants exploring various approaches to derive the necessary equations. Some guidance has been offered regarding simplifying the problem by using a single variable for the center's coordinates. There is no explicit consensus on the best approach yet.

Contextual Notes

Participants note the potential complexity of solving the equations simultaneously and express concerns about the results obtained, such as unexpected values for g. The discussion reflects the constraints of working with the given radius and the line equation.

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Homework Statement


Find an equation of the circle passing through:

A(-3,1) with radius 2 and centre on the line 2x-3y+3=0

Homework Equations


x2+y2+2gx+2fy+c=0
r2=g2+f2-c

The Attempt at a Solution


using this equation , i have found 2 equations
-6g+2f+c=-10 by putting (-3,1)

-2g+3f+3=0 (-g,-f) in the linear equation which passes through the centre

how can i use radius information here to get the third equatio n ?
 
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If A(-3,1) is on the circle, what do you know about its distance to the center?
Alternatively: Just plug in the radius in your second "relevant equation".

(It would be easier to start with the line of the centers and just one unknown variable, but your approach works as well).
 
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alijan kk said:
and centre at 2x-3y+3=0
I think you meant "and centre on (the line) 2x - 3y + 3 = 0."
 
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mfb said:
If A(-3,1) is on the circle, what do you know about its distance to the center?
Alternatively: Just plug in the radius in your second "relevant equation".

(It would be easier to start with the line of the centers and just one unknown variable, but your approach works as well).
(-3,1) (-g,-f) distance between them is equal to r

g2+f2+2f+6g+10=r2

g2+f2-c=r2

i get a weird anwer by solving simultaneously ,,, like g=0
 
mfb said:
If A(-3,1) is on the circle, what do you know about its distance to the center?
Alternatively: Just plug in the radius in your second "relevant equation".

(It would be easier to start with the line of the centers and just one unknown variable, but your approach works as well).
(-3,1) (-g,-f) distance between them is equal to r

g2+f2+2f+6g+10=r2

g2+f2-c=r2

i get a weird anwer by solving simultaneously ,,, like g=0

which is the better and easier strategy ?
 
I would start with the suggestion at the end of my post. The center is on the line 2x-3y+3=0? Let its x value be x0, calculate its y-value, calculate the distance to A(-3,1) and require that this distance is 2. A single variable, a single equation to satisfy.
 
@alijan kk: Are you going to share with us what you got? You should have two answers.
 

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