Finding the nth Power of a 2x2 Matrix | A^n = PD^nP^-1 Formula Not Required

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SUMMARY

The discussion focuses on finding the nth power of the matrix A = |1 1| |0 0| without using the A^n = PD^nP^-1 formula. Participants confirm that calculating successive powers of the matrix reveals a clear pattern, making it feasible to derive a formula based on these observations. The consensus is that for this specific matrix, a straightforward approach of pattern recognition is effective, especially in a Calculus 4 context.

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Homework Statement



Find the nth power of the matrix A,

|1 1|
|0 0|

Homework Equations



The Attempt at a Solution



My guess is the A^n = PD^nP^-1 formula. But my prof says not use to eigenvalues and eigenvectors. Is it possible to solve this without using the formula A^n = PD^nP^-1 ?
 
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Is it specifically {1\, 1 \choose 0\, 0} or a more general problem?

Have you tried calculating any powers of that particular matrix?

{1\, 1 \choose 0\, 0}{1\, 1 \choose 0\, 0} = {1\, 1 \choose 0\, 0}

So...
 
Let's say more general.

Is it just calculating successive powers and finding some pattern to base a formula off of?
 
tracedinair said:
Let's say more general.

Is it just calculating successive powers and finding some pattern to base a formula off of?

It depends what level a course the problem is being asked in, really. For something like this, the pattern is incredibly obvious. In general, there may not be a pattern though... But, if your teacher/professor is looking for a simple solution without much technical mathematics, which it sounds like, doing some sample calculations and finding a pattern is a solid plan (especially for this particular matrix).
 
This is Calculus 4. Pattern finding is probably the most obvious solution. Thanks for the help.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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