Finding the Nth Root of a Number without a Calculator

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Discussion Overview

The discussion centers around methods for finding the nth root of a number without the use of a calculator. Participants explore various approaches, including iterative methods and theoretical underpinnings, while considering the practicality and efficiency of these methods.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant inquires about a "pencil and paper" method for finding nth roots, expressing skepticism about trial and error methods.
  • Another participant proposes an iterative formula for improving guesses of the nth root, demonstrating it with an example of estimating the cube root of 10.
  • A later reply notes that while the proposed method is still a form of trial and error, it converges quickly to an accurate result, achieving significant precision in a few iterations.
  • One participant shares a link to a resource on Newton's method for further theoretical context.
  • Another participant discusses the case of n = -1, suggesting a specific formula that avoids divisions, which can be useful for performing divisions more efficiently.

Areas of Agreement / Disagreement

Participants generally agree on the effectiveness of the iterative method for finding nth roots, but there is no consensus on whether it constitutes a true alternative to trial and error, as some still view it as a form of trial and error.

Contextual Notes

The discussion does not resolve the limitations of the methods proposed, such as the dependence on initial guesses or the potential for convergence issues in certain cases.

Holocene
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Is there any "pencil and paper" method to find the nth root of a number?

Since multiplying a number by itself any number of times quickly yeilds extremely large numbers, trial and error might seem to pinpoint the root of a number, so long as it is a perfect square or cube or whatever.

But, is there any real way to pinpoint the root of a number without using a calculator or trial and error?
 
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To compute the nth root of a number Y, just make some guess X and then improve that guess using the formula:

[tex]\left(1-\frac{1}{n}\right)X + \frac{Y}{n X^{n-1}}[/tex]

You can iterate this to make further improvements. E.g. suppose you want to estimate the cube root of 10. Then you can take X = 2. the formula gives: 4/3 + 10/(3*4) = 2 + 1/6

If you then take X = 2+1/6 and insert that in the formula to get 2.1545. Iterating again gives 2.15443469224. Now, believe it or not but:

2.15443469224^3 = 10.0000000307 :smile:
 
If you want to know the general theory behind the above method, see http://planetmath.org/encyclopedia/NewtonsMethod.html .
 
Last edited by a moderator:
So, this is still trial and error, but it converges very fast. At each step you double to correct number of digits. You go from a wild guess to a number that is correct to ten significant digits in about four iterations.
 
Count Iblis said:
To compute the nth root of a number Y, just make some guess X and then improve that guess using the formula:

[tex]\left(1-\frac{1}{n}\right)X + \frac{Y}{n X^{n-1}}[/tex]

You can iterate this to make further improvements. E.g. suppose you want to estimate the cube root of 10. Then you can take X = 2. the formula gives: 4/3 + 10/(3*4) = 2 + 1/6

If you then take X = 2+1/6 and insert that in the formula to get 2.1545. Iterating again gives 2.15443469224. Now, believe it or not but:

2.15443469224^3 = 10.0000000307 :smile:

wow, that's pretty neat. Thanks!
 
The case n = -1 is also very useful. In that case X = 1/Y but Newton's method gives:

[tex]2X - X^{2} Y[/tex]

Since there are no divisions in here, you can use it to do divisions. It's much faster than long division.
 

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