Finding the Percentage Increase in y When x is Doubled

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The discussion focuses on calculating the percentage increase in y when x is doubled, given that y is directly proportional to x squared (y = kx²). When x is increased by 100%, resulting in x being doubled (x₂ = 2x₁), the new value of y (y₂) becomes four times the original value (y₂ = 4y₁). Consequently, the percentage increase in y is determined to be 300%, calculated using the formula ((y₂ - y₁) / y₁) * 100.

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oic. thanks a lot.

y is directly proportional to x2
x is increased by 100%
find the percentage increase in y.

so,
y= k x2

then y= k x2
y=k 4 x2

so 4 x2 is already increased by 100%?
then to find k which is
y=k 4 x2
k= y/ 4 x2

find the percentage increase in y,
so what i did was :
y= y/4 x2 *100 x2 :confused:

can somebody helpp to correct it??
thanks lotsa.:smile:
 
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First, set up your general equation:
[tex]y=kx^{2}[/tex]
Now, let [itex](x_{1},y_{1}),(x_{2},y_{2})[/tex] be two pairs of x and y values that satisfies your equation, that is: <br /> [tex]y_{1}=kx_{1}^{2}[/tex]<br /> and<br /> [tex]y_{2}=kx_{2}^{2}[/tex]<br /> <br /> Now, let [itex]x_{2}[/tex] represent a 100% increase of [itex]x_{1}[/itex], that is:<br /> [itex]x_{2}=2x_{1}[/tex]<br /> <br /> Now, calculating [itex]y_{2}[/itex], we find:<br /> [tex]y_{2}=kx_{2}^{2}=k(2x_{1})^{2}=4kx_{1}^{2}=4y_{1}[/tex]<br /> Thus, calculating the percentwise increase, we have:<br /> [tex]\frac{y_{2}-y_{1}}{y_{1}}*\frac{100}{100}=\frac{4y_{1}-y_{1}}{y_{1}}*\frac{100}{100}=3*\frac{100}{100}=\frac{300}{100}[/tex]<br /> Thus, if x increases with 100% , y increases with 300%.[/itex][/itex][/itex]
 
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