Finding the position vector for translated frame of reference

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SUMMARY

The discussion centers on finding the position vector for a translated frame of reference, specifically the vector ##\vec r = (8t - 1) \hat i + (6t - 2) \hat j##. The user seeks clarification on the reasoning behind the signs in the vector components, particularly at t = 0, where the position is set to -1i -2j. The conversation also touches on the relationship between vectors ##\vec R##, ##\vec r##, and ##\vec r\:'## in the context of relative frames of reference, emphasizing the need for an inertial frame for valid calculations.

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  • Understanding of vector notation and operations in physics
  • Familiarity with the concept of translated frames of reference
  • Knowledge of inertial frames and their properties
  • Basic principles of relative motion in classical mechanics
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This discussion is beneficial for physics students, educators, and anyone involved in mechanics, particularly those focusing on vector analysis and relative motion in different frames of reference.

simphys
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Homework Statement
Please refer to the picture, I don't really have a question problem.
I was posed the question on how I would model what the position would be when the frame of reference is translated as shown on the picture.
Relevant Equations
##\vec r = 8t \hat i + 6t \hat j## for the y-x reference framse.
what would be the y'-x' ##\vec r## vector be?

I think it is
##\vec r = (8t - 1) \hat i + (6t - 2) \hat j## (not sure whether it is correct or not.)
I thought about it as at t = 0 the position needs to be -1i -2j so that is why I took the signs in the y'-x' frame position vector as a - instead of + signs for 1 and 2.

Is it ok to reason like this or do I need to derive it from somewhere else? I am not very acquianted with translation of the axes that's why I am asking.
Thanks in advance.

1658132327542.png
 
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What is the origin of x' y' system as measured in the x y system?
 
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drmalawi said:
What is the origin of x' y' system as measured in the x y system?
in points (1,2) = (x,y)
 
1658133200085.png

can you find a relation for the vectors ## \vec R##, ##\vec r## and ##\vec r\:'##?
 
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drmalawi said:
What is the origin of x' y' system as measured in the x y system?
oh wait, isn't this actually the 'relative frames of references' that are used to describe relative motion?
than it becomes r_x/p = r_x'/x + r_p/x' (where the condition was that it should be an inertial frame aka cst velocity or at rest for it to be valid)
 
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drmalawi said:
View attachment 304325
can you find a relation for the vectors ## \vec R##, ##\vec r## and ##\vec r\:'##?
yep exactly my post #5 no?
 
simphys said:
aka cst
?
 
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drmalawi said:
?
constant, apologies.
 
  • #10
simphys said:
constant, apologies.
np glhf
 
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