Finding the potential energy of a time dependent force

Click For Summary
SUMMARY

The discussion centers on calculating the potential energy of a pendulum subjected to a time-dependent force, specifically using the formula U=-∫F*v*dt. The force is defined as F=(m*g/3)*cos(ω*t), leading to a potential energy expression that results in a negative value. Participants clarify that the change in potential energy should be positive when the force and displacement are in the same direction, prompting questions about the application of the negative gradient in force calculations.

PREREQUISITES
  • Understanding of Lagrangian mechanics
  • Familiarity with potential energy concepts
  • Knowledge of time-dependent forces
  • Basic calculus for integration
NEXT STEPS
  • Study Lagrangian mechanics in detail, focusing on systems with time-dependent forces
  • Explore the derivation of potential energy in dynamic systems
  • Learn about the implications of force direction on potential energy calculations
  • Investigate the mathematical treatment of integrals involving trigonometric functions
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in advanced dynamics and the application of Lagrangian mechanics to real-world systems.

GhostLoveScore
Messages
149
Reaction score
9
Homework Statement
Force on an object is F=(m*g/3) *cos(ω*t) in x direction. Find potential energy
Relevant Equations
U=- ∫(F dx) = - ∫(F*v*dt)
U=-∫F*v*dt= -∫(m*g/3)*cos(ω*t) dt = -(m*g/3 )* (v/ω )* sin(ω*t)

except that according to the official solution, I should be getting positive sign instead of negative. Am I doing something wrong?
 
Physics news on Phys.org
May I ask the origin of this question?
 
hutchphd said:
May I ask the origin of this question?

Yes, I have to find a Lagrangian of the pendulum that has a force acting on its top end (which is free to move).
 
The change in potential energy of the object should be positive if Fdx is positive.
 
  • Like
Likes   Reactions: GhostLoveScore
hutchphd said:
The change in potential energy of the object should be positive if Fdx is positive.

OK, then why are we calculating force F as F=-∇U (with minus)
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
10
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
1K