Finding the potential energy of a gravitational force?

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Homework Help Overview

The discussion revolves around finding the potential energy function associated with the gravitational force between two masses, as described by the equation F(r)=GM1M2/r^2. The original poster is attempting to derive the potential energy function U(x) and is also inquiring about the work required to change the separation between the masses.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to integrate the force to find the potential energy function but expresses confusion over the sign of the result. Some participants question the sign convention used in the force equation and its implications for potential energy.

Discussion Status

Participants are exploring the relationship between force and potential energy, with some guidance provided regarding the sign convention. There is an acknowledgment of the original poster's calculations, but no explicit consensus on the correct interpretation has been reached.

Contextual Notes

There is a mention of the potential energy approaching zero as the distance increases, and the original poster is seeking a clue for the work calculation without a complete solution being provided.

CoreanJesus
Sorry if something is wrong... this is my first ever post
1. Homework Statement

The Question:
In one dimension, the magnitude of the gravitational force of attraction between a particle of mass M1, and one of mass M2 is given by:
F(r)=GM1M2/r^2
Where G is a constant and x is the distance between the particles.

a) What is the potential energy function U(x)? Assume that U(x) -> 0 as x -> infinity.
b) How much work is required to increase the separation of the particles from x=x1 to x=x1+d?

Homework Equations


F(r)=-dU/dx

The Attempt at a Solution


For a), The answer given is -GM1M2/r but I keep getting a positive equation...
∫-dU=∫GM1M2/r^2
-U=-GM1M2/r
U=GM1M2/r
For b) I just need a clue as to how to start...
 
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CoreanJesus said:
In one dimension, the magnitude of the gravitational force of attraction between a particle of mass M1, and one of mass M2 is given by:
F(r)=GM1M2/r^2
The force is attractive, i. e. towards smaller r. It would be better to add a minus sign here, otherwise the sign convention is confusing.
CoreanJesus said:
For b) I just need a clue as to how to start...
What is the potential energy at the described places?
 
mfb said:
The force is attractive, i. e. towards smaller r. It would be better to add a minus sign here, otherwise the sign convention is confusing.What is the potential energy at the described places?
No potential energy is given...
 
You just calculated it!
 
Oh :D Thank You!
 

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