Finding the roots of a quadratic equation

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Homework Help Overview

The discussion revolves around finding the roots of a quadratic equation, specifically through the manipulation of parameters α and β. Participants are examining the correctness of a working example and exploring the implications of their choices in defining these parameters.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the method of forming a quadratic equation from given roots and question the validity of setting α equal to β. There is also an inquiry into the origins of specific combinations used in the example.

Discussion Status

The discussion is ongoing, with some participants offering guidance on checking work and clarifying notation. There is a recognition of potential confusion regarding the symbols used, and participants are actively engaging with each other's reasoning.

Contextual Notes

There is a mention of checking previous examples for correctness, and participants are navigating the implications of their choices in defining the roots. The notation used has led to some misunderstandings that are being addressed.

chwala
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Homework Statement
Kindly see the attached problem below
Relevant Equations
sum and products of roots of a quadratic equation
1617241655897.png
 
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find my working on this below;

1617241722760.png

1617241762395.png

i would like you to check my working...is it correct?
 
After you find k (which you do correctly) just solve the equation explicitly as a check. You don't need my help.
 
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i should be correct, checking with a previous example...
1617246725763.png


if i let ##α=3## and ##β=1##, then ##(x-3)(x-1)=x^2-4x+3##, ##p=4## and ##q=3##
on forming the required quadratic with form ##\frac {α}{β^2}## and ##\frac {β}{α^2}##,
we shall have,
##(x-\frac {1}{9}##)##(x-3)##=##x^2-\frac {28}{9}x##+##\frac {1}{3}## which is in the required form...
similarly using the same thinking, and picking the roots ##α=-3## and ##β=-3## would yield the required form that i had shown in my working...
problem is can we let ##α=β?##
 
Last edited:
chwala said:
i should be correct, checking with a previous example...
View attachment 280707

if i let ##∝=3## and ##β=1##,
Where does that combination come from? Did you mean α=β=3?
Btw, ∝ means "is proportional to". It is not a form of α (or in LaTeX, ##\alpha##).
 
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haruspex said:
Where does that combination come from? Did you mean α=β=3?
Btw, ∝ means "is proportional to". It is not a form of α (or in LaTeX, α).

yeah, let me amend that...my eyes did not see that well..am getting oldo0)
 

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