Finding the slop of a string (Waves)

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Homework Statement



Wave motion is characterized by two velocities: the velocity with which the wave moves in the medium (e.g., air or a string) and the velocity of the medium (the air or the string itself).

Consider a transverse wave traveling in a string. The mathematical form of the wave is

[tex]y(x,t) = Asin(kx - \omega t)[/tex]

Find the slope of the string [tex]\frac{dy(x,t)}{dx}[/tex] as a function of position x and time t.

Homework Equations





The Attempt at a Solution



So to find the slope of that equation, I would just need to take it's derivative. x is the variables, and [tex]\omega[/tex], A, t are constants. I would also need to use the chain rule when doing the derivative of sin.

So I get: [tex]\frac{dy(x,t)}{dx} = (Acos(kx - \omega t))*(k - \omega t)[/tex]

but it says I'm wrong. Any suggestions where I went wrong?
 
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[tex]\frac d {dx} ( kx- \omega t)[/tex] = ?
 
Integral said:
[tex]\frac d {dx} ( kx- \omega t)[/tex] = ?

would I treat the x as a variable and t as a constant?