Finding the Solution for a Tricky ln Equation

[dnt]

ln (x+1) = x-3

i know ln is log base e so the equation becomes:

e^(x-3) = x + 1

and i can rearrange using algebra to get:

e^x = e^3(x+1)

but now I am stuck...how can i separate the x's to solve for it?

thanks.

 

[StatusX]

You can't write the solution x in terms of elementary functions like e^x and ln(x). You'll probably have to use a calculator to get an approximate numerical solution.

 

[dnt]

ah thanks.

 

[HallsofIvy]

In general, there is no "algebraic" solution for problems that involve both a transcendental function of x (such as e^x) and non-transcendental function of x (such as x+1). You will have to use some approximation method (such as graphing y= e^x-3 and y= x+1 and seeing where they cross).