Finding the Sum of an Alternating Geometric Sequence

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The discussion focuses on finding the sum of an alternating geometric sequence with terms 30, -31, 32, and -32. The sequence can be separated into two parts, but the lengths differ, complicating the sum calculation. A general formula is proposed: for odd n (n=2m+1), the sum is 1/4(-3^(2m+1)+1), and for even n (n=2m), it is 1/4(3^(2m+1)+1). The combined formula for both cases is 1/4((-1)^n * 3^(n+1) + 1). Setting n=1 in this formula yields a sum of -1/2.
Sarah00
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Hi!

If I have a sequence that its first 4 terms are:

30, -31, +32, -32

The pattern is geometric sequence but has alternating signs..

How can I find its sum ..

I know it is composed of 2 sequences ..

However, when I try to separate the 2 sequences .. I get them of different "lengths"

In other words, it is (30+32+34) - (31+33) for 5 terms

but for 4 terms I get:
In other words, it is (30+32) - (31+33)How can I get general formula for both ..

(-1)k helps ! but how! and what about the number of termsThanks!
 
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Further to my previous post ..

screenshot_158.png
 
This is the book's answer:
screenshot_158.png
 
When ##n## is odd that is ##n=2m+1## you obtain ## \frac{1}{4}(-3^{2m+1}+1)##, when is even ##n=2m## you obtain ## \frac{1}{4}(3^{2m+1}+1)##. In order to obtain both you must have ## \frac{1}{4}((-1)^{n}3^{n+1}+1)## (this is obtained merging the two previous...)
 
Sarah00 said:
Further to my previous post ..

screenshot_158.png

If you set ##n = 1##, then your formula gives ##S = -1/2##
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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