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http://session.masteringphysics.com/problemAsset/1026448/22/yg.10.59.jpg

Find the tension in the cable.

Find the horizontal and vertical component of the force exerted on the beam at the wall.

How would I solve this?

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- Thread starter cece
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- #1

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http://session.masteringphysics.com/problemAsset/1026448/22/yg.10.59.jpg

Find the tension in the cable.

Find the horizontal and vertical component of the force exerted on the beam at the wall.

How would I solve this?

- #2

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- #3

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- #4

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You should know that Newton's second law [tex] \vec{F}_{NET} = m\vec{a} [/tex] breaks down into:

[tex] F_x = F_1 + F_2 = 0 [/tex]

[tex] F_y = F_3 + F_4 + F_5 + F_6 = 0 [/tex]

Now all you have to do is identify what these components are.

And you should know that to find the net torque, you simply add the torques due to each force. To make life simple, take the torque about the right end of the beam. If we take counter clockwise to be positive, you'll have:

[tex] \tau_{NET} = F_7(R_7) - F_8(R_8) + F_9(R_9) = 0 [/tex]

One of these torques will go to zero. Taking the coordinate system into account, it will be the torque caused my F9. Why is this? Again, you would do well to make a free body diagram. One for the forces, and one for the torques.

[tex] F_x = F_1 + F_2 = 0 [/tex]

[tex] F_y = F_3 + F_4 + F_5 + F_6 = 0 [/tex]

Now all you have to do is identify what these components are.

And you should know that to find the net torque, you simply add the torques due to each force. To make life simple, take the torque about the right end of the beam. If we take counter clockwise to be positive, you'll have:

[tex] \tau_{NET} = F_7(R_7) - F_8(R_8) + F_9(R_9) = 0 [/tex]

One of these torques will go to zero. Taking the coordinate system into account, it will be the torque caused my F9. Why is this? Again, you would do well to make a free body diagram. One for the forces, and one for the torques.

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