Finding the velocity of an emitted particle from a decay

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The discussion focuses on calculating the velocity of a pion produced from the decay of a rho meson, initially at rest with a total energy of 775.5 MeV. Conservation of energy and momentum principles are applied, noting that the initial momentum is zero, leading to equal and opposite momenta for the gamma ray and pion. The equations E = pc and E² = p²c² + m²c⁴ are referenced to relate energy and momentum. The conversation suggests using 4-vectors to systematically combine conservation laws for a clearer solution. The participant expresses confidence in understanding the problem after receiving guidance on the equations.
HarryO
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Homework Statement
A rho meson, rest mass of 775.5 MeV at rest decays into a pion, rest mass of 139.6 MeV and a gamma ray with 0 rest mass, find the velocity of the pion produced in the decay
Relevant Equations
E=pc
E^2 = p^2*c^2 + m^2*c^4
So I know that the total energy of the system initially is 775.5MeV, because the meson is at rest. Also by conservation of energy I know that the total final energy of the system is the same thing. I also know that the initial momentum of the system is 0 because the particle is at rest. This means that the total momentum of the final state must be 0 as well, which I think means that the mometym of the gamma ray and pion must be equal and opposite. So I get.

Eϒ = pc
p = ϒmπvπ

ϒmπvπ = Eϒ/c

However from here I am stuck because I do not know how to find the energy of the gamma ray.
 
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HarryO said:
Homework Statement:: A rho meson, rest mass of 775.5 MeV at rest decays into a pion, rest mass of 139.6 MeV and a gamma ray with 0 rest mass, find the velocity of the pion produced in the decay
Homework Equations:: E=pc
E^2 = p^2*c^2 + m^2*c^4

So I know that the total energy of the system initially is 775.5MeV, because the meson is at rest. Also by conservation of energy I know that the total final energy of the system is the same thing. I also know that the initial momentum of the system is 0 because the particle is at rest. This means that the total momentum of the final state must be 0 as well, which I think means that the mometym of the gamma ray and pion must be equal and opposite. So I get.

Eϒ = pc
p = ϒmπvπ

ϒmπvπ = Eϒ/c

However from here I am stuck because I do not know how to find the energy of the gamma ray.

You need to combine the equations for conservation of momentum and conservation of energy.
 
A systematic way is to use 4-vectors. We have:
$$P_\rho =(E,0,0,0)$$
$$P_\pi =(E',p',0,0)$$
$$P_\gamma= (E",p",0,0)$$

Now use the conservation laws to relate the quantities and don't forget to use:

$$E^2-p^2=m^2$$ or $$P_\gamma+P_\pi=P_\rho$$ for each of above relation.

Here I have taken c=1
 
Okay thank you! I think I have it now.
 

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