Finding the velocity of an emitted particle from a decay

Click For Summary

Homework Help Overview

The discussion revolves around a decay process involving a rho meson that decays into a pion and a gamma ray. The original poster is working with the conservation of energy and momentum principles to find the velocity of the emitted pion. The initial conditions include the rho meson being at rest with a total energy of 775.5 MeV.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply conservation laws but encounters difficulty in determining the energy of the gamma ray. Some participants suggest combining equations for conservation of momentum and energy, while another proposes using 4-vectors to relate the quantities involved.

Discussion Status

The discussion is active, with participants exploring different methods to approach the problem. Guidance has been offered regarding the use of conservation laws and 4-vectors, indicating a productive direction in the conversation.

Contextual Notes

Participants are working under the constraints of the problem statement, which includes specific rest masses and the requirement to find the velocity of the pion without providing complete solutions. There is an emphasis on understanding the relationships between energy and momentum in the context of particle decay.

HarryO
Messages
3
Reaction score
0
Homework Statement
A rho meson, rest mass of 775.5 MeV at rest decays into a pion, rest mass of 139.6 MeV and a gamma ray with 0 rest mass, find the velocity of the pion produced in the decay
Relevant Equations
E=pc
E^2 = p^2*c^2 + m^2*c^4
So I know that the total energy of the system initially is 775.5MeV, because the meson is at rest. Also by conservation of energy I know that the total final energy of the system is the same thing. I also know that the initial momentum of the system is 0 because the particle is at rest. This means that the total momentum of the final state must be 0 as well, which I think means that the mometym of the gamma ray and pion must be equal and opposite. So I get.

Eϒ = pc
p = ϒmπvπ

ϒmπvπ = Eϒ/c

However from here I am stuck because I do not know how to find the energy of the gamma ray.
 
Physics news on Phys.org
HarryO said:
Homework Statement:: A rho meson, rest mass of 775.5 MeV at rest decays into a pion, rest mass of 139.6 MeV and a gamma ray with 0 rest mass, find the velocity of the pion produced in the decay
Homework Equations:: E=pc
E^2 = p^2*c^2 + m^2*c^4

So I know that the total energy of the system initially is 775.5MeV, because the meson is at rest. Also by conservation of energy I know that the total final energy of the system is the same thing. I also know that the initial momentum of the system is 0 because the particle is at rest. This means that the total momentum of the final state must be 0 as well, which I think means that the mometym of the gamma ray and pion must be equal and opposite. So I get.

Eϒ = pc
p = ϒmπvπ

ϒmπvπ = Eϒ/c

However from here I am stuck because I do not know how to find the energy of the gamma ray.

You need to combine the equations for conservation of momentum and conservation of energy.
 
A systematic way is to use 4-vectors. We have:
$$P_\rho =(E,0,0,0)$$
$$P_\pi =(E',p',0,0)$$
$$P_\gamma= (E",p",0,0)$$

Now use the conservation laws to relate the quantities and don't forget to use:

$$E^2-p^2=m^2$$ or $$P_\gamma+P_\pi=P_\rho$$ for each of above relation.

Here I have taken c=1
 
Okay thank you! I think I have it now.
 

Similar threads

Replies
4
Views
2K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
5K
Replies
1
Views
1K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K