Finding the velocity of an emitted particle from a decay

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 2K views
HarryO
Messages
3
Reaction score
0
Homework Statement
A rho meson, rest mass of 775.5 MeV at rest decays into a pion, rest mass of 139.6 MeV and a gamma ray with 0 rest mass, find the velocity of the pion produced in the decay
Relevant Equations
E=pc
E^2 = p^2*c^2 + m^2*c^4
So I know that the total energy of the system initially is 775.5MeV, because the meson is at rest. Also by conservation of energy I know that the total final energy of the system is the same thing. I also know that the initial momentum of the system is 0 because the particle is at rest. This means that the total momentum of the final state must be 0 as well, which I think means that the mometym of the gamma ray and pion must be equal and opposite. So I get.

Eϒ = pc
p = ϒmπvπ

ϒmπvπ = Eϒ/c

However from here I am stuck because I do not know how to find the energy of the gamma ray.
 
Physics news on Phys.org
HarryO said:
Homework Statement:: A rho meson, rest mass of 775.5 MeV at rest decays into a pion, rest mass of 139.6 MeV and a gamma ray with 0 rest mass, find the velocity of the pion produced in the decay
Homework Equations:: E=pc
E^2 = p^2*c^2 + m^2*c^4

So I know that the total energy of the system initially is 775.5MeV, because the meson is at rest. Also by conservation of energy I know that the total final energy of the system is the same thing. I also know that the initial momentum of the system is 0 because the particle is at rest. This means that the total momentum of the final state must be 0 as well, which I think means that the mometym of the gamma ray and pion must be equal and opposite. So I get.

Eϒ = pc
p = ϒmπvπ

ϒmπvπ = Eϒ/c

However from here I am stuck because I do not know how to find the energy of the gamma ray.

You need to combine the equations for conservation of momentum and conservation of energy.
 
A systematic way is to use 4-vectors. We have:
$$P_\rho =(E,0,0,0)$$
$$P_\pi =(E',p',0,0)$$
$$P_\gamma= (E",p",0,0)$$

Now use the conservation laws to relate the quantities and don't forget to use:

$$E^2-p^2=m^2$$ or $$P_\gamma+P_\pi=P_\rho$$ for each of above relation.

Here I have taken c=1
 
Okay thank you! I think I have it now.