Finding the voltage after current was found

[Gbox]

Homework Statement

Find $v_0$

Homework Equations

looking for which way is the best

The Attempt at a Solution

Using parallel and series resistor I have found that $i=0.006 A$ what should I do next?

 

[SammyS]

Homework Statement

Find $v_0$

Homework Equations

looking for which way is the best

The Attempt at a Solution

Using parallel and series resistor I have found that $i=0.006 A$ what should I do next?

What is the voltage drop across R₁ ?

Added in Edit:
By the way: That current looks suspiciously low.

 

[gneill]

If you have i then you can find the potential drop across R1. Go from there.

Personally I'd probably have taken a different approach and transformed the source voltage and R1 into a Norton equivalent, absorbing R3 into it, then convert back to Thevenin and swallow up R4 too. That would leave a simple voltage divider at the end.

 

[Gbox]

What I did is:
$180+60=240$ than $\frac{240*80}{240+80}=60$ and than $60+20=80k\Omega$

 

[gneill]

What I did is:
$180+60=240$ than $\frac{240*80}{240+80}=60$ and than $60+20=80k\Omega$

Yes, that's fine.

 

[Gbox]

So I found that the voltage on $R_1=120$ so I have $480-120=360$ finding the current on $R_{4+2}$ is $0.0015A$ so the voltage on $R_4$ is $90$ and overall it is $360-90=270$?

 

[gneill]

That works.

 

[ehild]

So I found that the voltage on $R_1=120$ so I have $480-120=360$ finding the current on $R_{4+2}$ is $0.0015A$ so the voltage on $R_4$ is $90$ and overall it is $360-90=270$?

Correct!