Finding the wavelength of this wave

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The discussion revolves around calculating the wavelength of a wave based on its total distance and the number of complete cycles. The total distance traveled by the wave is 4.8 meters, with 3 complete cycles present, leading to the conclusion that the wavelength is 4.8 meters divided by 3, resulting in 1.6 meters. There is confusion regarding the mention of "2 wavelengths," which is clarified as incorrect since only 3 cycles are observed. Additionally, it is noted that while frequency can change, the product of frequency and wavelength remains constant, as expressed in the equation c = f*lambda. The conversation effectively resolves the initial confusion about wavelength calculation and its relationship with frequency.
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Homework Statement


Okay, here is a photo of the wave I did on a graphing program: http://img221.imageshack.us/i/wavelengthsgraph.jpg/

Now the total distance the wave travels is 4.8 M. There are 3 crests and 3 troughs, but there is only 2 wavelengths throughout the wave. This confuses me.

Homework Equations


To finding the wavelength is it 4.8/2? Or 4.8 divided by 3?


The Attempt at a Solution


I tried 4.8/3, but I didn't feel to comfortable with the answer since the wavelengths do not seem to be 1.6 M long, so would it become 4.8/2=2.4M?

And how would I know how to determine the answer for future equations? Thanks in advance.
 
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There are only 3 complete cycles of that particular wave in 4.8 meters, so the wavelength is 4.8/3. Not sure what you mean by "there is only 2 wavelengths throughout the wave."
 
fss said:
There are only 3 complete cycles of that particular wave in 4.8 meters, so the wavelength is 4.8/3. Not sure what you mean by "there is only 2 wavelengths throughout the wave."

So the wavelength is essentially the total distance/complete number of cycles?
 
Yes, essentially.
 
fss said:
Yes, essentially.

Wow, okay thanks for this. Solved most of the confusion I had over this. :smile:
 
Just one more question: If the frequency is changed, the velocity and wavelength remain the same, right?
 
No...

c = f*lambda

c stays the same.
 

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