Finding the wavelength of this wave

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SUMMARY

The wavelength of a wave can be calculated by dividing the total distance traveled by the number of complete cycles. In this discussion, the total distance is 4.8 meters with 3 complete cycles, leading to a wavelength of 4.8/3, which equals 1.6 meters. The confusion regarding the number of wavelengths is clarified, confirming that the wavelength is determined by the total distance divided by the number of cycles. Additionally, the relationship between frequency, velocity, and wavelength is established through the equation c = f*λ, indicating that changes in frequency do not affect the velocity and wavelength if the speed of the wave remains constant.

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  • Understanding of wave properties, including wavelength and frequency
  • Familiarity with basic algebra for calculations
  • Knowledge of the wave equation c = f*λ
  • Experience with graphing tools to visualize waveforms
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Homework Statement


Okay, here is a photo of the wave I did on a graphing program: http://img221.imageshack.us/i/wavelengthsgraph.jpg/

Now the total distance the wave travels is 4.8 M. There are 3 crests and 3 troughs, but there is only 2 wavelengths throughout the wave. This confuses me.

Homework Equations


To finding the wavelength is it 4.8/2? Or 4.8 divided by 3?


The Attempt at a Solution


I tried 4.8/3, but I didn't feel to comfortable with the answer since the wavelengths do not seem to be 1.6 M long, so would it become 4.8/2=2.4M?

And how would I know how to determine the answer for future equations? Thanks in advance.
 
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There are only 3 complete cycles of that particular wave in 4.8 meters, so the wavelength is 4.8/3. Not sure what you mean by "there is only 2 wavelengths throughout the wave."
 
fss said:
There are only 3 complete cycles of that particular wave in 4.8 meters, so the wavelength is 4.8/3. Not sure what you mean by "there is only 2 wavelengths throughout the wave."

So the wavelength is essentially the total distance/complete number of cycles?
 
Yes, essentially.
 
fss said:
Yes, essentially.

Wow, okay thanks for this. Solved most of the confusion I had over this. :smile:
 
Just one more question: If the frequency is changed, the velocity and wavelength remain the same, right?
 
No...

c = f*lambda

c stays the same.
 

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