Finding the x and y intercepts

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To find the y-intercept of the function f(x) = sin(x)/(1+cos(x)), x should be set to 0, resulting in the point (0,0). The x-intercept is found by setting f(x) to 0, leading to the equation sin(x) = 0, which gives the point (π,0) as the correct x-intercept. The original discussion incorrectly identified both intercepts and confused the axes. It is essential to ensure that the function's definition is upheld, meaning each x-value must correspond to a unique y-value. The discussion highlights the importance of accurately applying mathematical principles when determining intercepts.
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f(x)=sin(x)/(1+cos(x))
So I set it equal to zero to find the y-intercept
sin(x)=0(1+cos(x))
x= 0,∏ so the y-int: (0,0) and (0,∏)

To find the x intercept I would substitute 0 for x so,
sin(0)/(1+cos(0))=y
0/1+1=y
y=0 so the x-int: (0,0)

would that be right?
 
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Unfortunately, there are a few mistakes. Firstly, you are confusing the x and y-axis a bit. To find the y-intercept you would set x=0 (the y-axis has equation x=0) and vice versa. Secondly, you listed the points (0,0) and (0,π). You can not have two points on a function with the same x-value. It violates the definition of a function. Surely you meant the points (0,0) and (π,0). Finally, you incorrectly solved the equation {\frac{\sin x }{1+cos x}}=0

Not only is it necessary for sin x to be zero, but 1+ cos x must also be nonzero. x = \pi does not fulfill this second requirement.

Edit: This post should probably be in the Homework & Coursework Questions section.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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