# Finding the yearly income from energy in W

1. Oct 2, 2012

### SereneKi

1. The problem statement, all variables and given/known data

Approximately 1.7*10^6 kg of water drops 60 m over Niagara Falls every second. 1*10^9 J of potential energy is lost every second by the falling water. If an electrical generating plant could convert all of the potential energy into electrical energy it would have a power output of 1*10^9 W. If the utility company sold this energy at an industrial rate of 0.8 cents per kW-hour, what would their yearly income be from this source (give your energy in dollars)?

2. Relevant equations

1 kW =1000 W
365 days=1 year
8760 hours = 1 year

3. The attempt at a solution

1*10^9 W -> 1*10^6 kW

1*10^6 kW * 60 sec/min * 60 min/hour = 3.6 *10^9

3.6 *10^9 * 0.008 = 2.88*10^7

2.88*10^7 * 8760 = 2.52*10^11

it says this is wrong. I have one shot left. what am I doing wrong?
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

2. Oct 3, 2012

### CWatters

This bit is wrong..

If the output is 1*10^6 kW then after one hour it has delivered 1*10^6 kWH. You only need to multiply that by the number of hours there are in a year and the price per kWH.