Solar Panels and Solar Radiation Flux Density Help - Very Confused

Click For Summary
The discussion centers on calculating solar power output and understanding solar radiation flux density. The initial calculations for power output from solar panels are based on daily energy production, but there is confusion regarding the appropriate time period due to varying daylight hours. Participants clarify that solar radiation flux density can be equated to intensity, measured in W/m², and emphasize the importance of considering the angle of inclination of the solar panels in calculations. There is also mention of using a pyranometer to measure solar radiation flux density, and the need to focus on peak output rather than total daily energy for accurate assessments. Overall, the conversation highlights the complexities of solar energy calculations and the significance of angle and intensity in determining efficiency.
  • #31
Steve4Physics said:
Agreed.No. It is meaningless to refer to the "intensity of the solar panel". The solar panel does not have an intensity. The intensity is the amount of power from the sun per square metre. 5.53W/m² is the intensity *calculated assuming the solar panels are 100% efficient*. So 5.53W/m² is not an accurate value of intensity (because efficiency is not 100%).

But we know the panels are only 20.8% efficient. So intensity must be (roughly 5 times) bigger than 5.53W/m².Yes but round to 3 sig. figs.No. First, 'example' is the wrong word. And we physicists don't use words like 'tremendous' in this context! Just say (for example) "300W/m² is an overestimate ...
'per day' is wrong. You = mean averaged over a day.
13.29055 is too many significant figures.

The most *accurate* values of intensity are the ones calculated allowing for efficiency. So you should be averaging the answers from 1c) and 2c), not from 1b) and 2b).
(204 + 26.6)/2 = 115Wm/s²
So the 300W/m² (assumed to be an annual average), compared to 115W/m², is roughly between two and three times too big.

Thank you for your reply and your continued insight.

2. c) Sorry my mistake, clearly I misused intensity here.

Question 3) "example" was the wording from the original question. Oh right, I will correct my average value also, thank you for remarking on that.

Can I verify that it would be correct to use an angle of 35 degrees when finding the intensity, as I have become a little uncertain?
 
Physics news on Phys.org
  • #32
etotheipi said:
Intensity is another word for energy flux density. But in common (maybe sloppy) parlance, people like to drop the word "density". So you just have to keep your wits about you as to whether someone is talking about the evaluated surface integral (formally flux), or the integrand (formally flux density)!
Yes indeed. In general, we have to be prepared to interpret loosely used terminology in context. It's very difficult for the younger students who have had little exposure to different terminologies.
 
  • Like
Likes etotheipi and AN630078
  • #33
AN630078 said:
Can I verify that it would be correct to use an angle of 35 degrees when finding the intensity, as I have become a little uncertain?
I can't verify that. The wording in the question is unclear. 35º is is simply my best guess using the available information, as I explained in message #21. Is this a written piece of work you have to hand-in? If so precede it with a statement such as:
"The direction of solar radiation relative to the panel is unclear. I have assumed an angle of incidence of 35º".
You will not be penalised if the angle is not 35º because the question is so obviously poorly-worded.
 
  • Like
Likes AN630078
  • #34
Steve4Physics said:
I can't verify that. The wording in the question is unclear. 35º is is simply my best guess using the available information, as I explained in message #21. Is this a written piece of work you have to hand-in? If so precede it with a statement such as:
"The direction of solar radiation relative to the panel is unclear. I have assumed an angle of incidence of 35º".
You will not be penalised if the angle is not 35º because the question is so obviously poorly-worded.
Thank you very much for your reply and for your advice, I admit I will probably use your statement. It is a question my physics tutor sent to me in a quantum physics revision package of questions, but I had not come across a homogenous problem to this before, at least not within the context. If you like, once I have feeback from them I can inform you of the angle demanded by the question. Thank you again 👍😁
 
  • #35
haruspex said:
I worried you might think that, but I assure you not. Hence the Like.
Thankyou!
 
  • #36
AN630078 said:
Thank you very much for your reply and for your advice, I admit I will probably use your statement. It is a question my physics tutor sent to me in a quantum physics revision package of questions, but I had not come across a homogenous problem to this before, at least not within the context. If you like, once I have feeback from them I can inform you of the angle demanded by the question. Thank you again 👍😁
You are welcome. Yes, it would be interesting to learn what the intended angle actually is!
 
  • Like
Likes AN630078

Similar threads

  • · Replies 9 ·
Replies
9
Views
3K
Replies
6
Views
1K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
0
Views
1K
Replies
2
Views
3K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
6K