How to Find the Number of Liters of Gas Used in a Gasoline Engine

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Homework Help Overview

The problem involves a multicylinder gasoline engine in an airplane, specifically focusing on calculating the liters of fuel consumed during one hour of operation based on energy input and output per revolution and the heat of combustion of the fuel.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the work done by the engine by subtracting the exhaust energy from the input energy and then converting this to fuel consumption. Some participants question the necessity of subtracting the exhausted energy, suggesting that the fuel used may depend solely on the input energy.

Discussion Status

The discussion is ongoing, with participants providing clarifications and questioning the original approach. There is a recognition of the need to ensure unit consistency in calculations, and some guidance has been offered regarding the interpretation of the energy values provided.

Contextual Notes

The problem is framed within the constraints of a homework assignment, which may impose specific methods or assumptions that are under discussion.

Benb591
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Homework Statement


The problem is "A multicylinder gasoline engine in an airplane, operating at 2.40
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10^3 rev/min, takes in energy 7.98
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10^3 J and exhausts 4.50
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10^3 J for each revolution of the crankshaft." and it wants me to find the liters of fuel consumed in 1 hr of operation if the heat of combustion of the fuel is 4.03
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10^7 J/L.

Homework Equations


Work done by an engine is Energy in - energy out

I then just tried to manipulate units since I was very confused...

The Attempt at a Solution


I did (7.98*10^3)-(4.5*10^3)*(2.4*10^3) to get the work done per minute. Then converted to work per hour by multiplying by 60. Then divided by the heat of combustion. This made my units come out as L/h revolutions, and as revolutions are unit-less I thought it would work but it did not...help!

Thank you,
Ben
 

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How many liters of fuel are used per engine revolution?
 
Two comments:

(1) The energies are given in J/revolution, so when you multiply by rev/minute the revolutions cancel and units come out right.

(2) Why subtract the exhausted energy? The fuel used depends on the input energy only.
 
Oh...ok it makes sense now thank you so much!
 

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