Finding the z-coordinate of the center of gravity for a region

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    Calculus Gravity
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The z-coordinate of the center of gravity for the region defined by the inequality (x/(z^3-1))^2 + (y/(z^3+1))^2 <= 1, with the bounds 0 <= z <= 1, is confirmed to be 7/16. Multiple participants in the discussion validate this result, indicating a consensus on the correctness of the calculation. This topic is rooted in calculus and geometric analysis, specifically focusing on the determination of center of gravity in three-dimensional regions.

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rman144
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(Moderator's note: thread moved from Calculus and Analysis)

I just need to know if my answer is correct for the following:

Find the z-coordinate of the center of gravity of the region:

(x/(z^3-1))^2 + (y/(z^3+1))^2<=1, 0<=z<=1.

I'm getting 7/16; am I in the ballpark? Thanks for any help.
 
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I got that value as well.
 
Thanks; glad to know I'm at least somewhat following this material.
 

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