Finding this set of values for x

[thomas49th]

Solve these simultaneous equations
y = -2x + 5
$$y = 2x^{2}-3x -16 = 0$$

I did that and got these pairs (which i checked are right)
x = 7/2, y = -2
x = -3, y = 11

Now the second part of the question is Hence, or otherwise, find the set of values of x which

$$y = 2x^{2}-3x -16 = > 5 - 2x$$

I don't know how to go about doing this last bit

 

[symbolipoint]

Initial steps for your inequality are to find the expression related to zero using the properties/axioms of inequality and find the critical points of x which satisfy the equality of 'expression' = 0.