1. The problem statement, all variables and given/known data A baseball pitcher makes a big mistake and throws the ball straight up. If it reaches a maximum height of 15 m. Find the times when the ball was 8.0 m above the ground. I already solved the variables needed Vi= 17 m/s Time the ball spent in the air= 3.5 s average velocity= 8.6 m/s balls velocity when its displacement equals to 8.0= ±12 m/s a= -9.8 m/s2 2. Relevant equations Vf2=vi2+2ad Vf=Vi+at d=Vit+½at2 3. The attempt at a solution I managed to find the first time by finding the balls velocity when its first 8.0 m from the ground by using the equation Vf2=vi2+2ad then plugging that into Vf=Vi+at to get a time of 0.56 s. But I just can't seem to be able to find the time for when the ball comes back down and crosses the 8.0 m mark again.