Finding Vector Components using Trigonometry

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Homework Help Overview

The discussion revolves around finding the X and Y components of a vector using trigonometric functions. The original poster presents a scenario involving a vector with a given angle and magnitude, seeking assistance in determining its components.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to construct a triangle to visualize the problem and initially uses tangent to find the length of a line, expressing uncertainty about their calculations. They later apply the Pythagorean theorem but encounter unexpected results. Some participants suggest using sine and cosine functions for the calculations, providing formulas for the components.

Discussion Status

Participants are exploring different trigonometric functions to find the vector components. Some guidance has been offered regarding the correct functions to use, and the original poster has attempted the suggested approach, reporting their results for verification.

Contextual Notes

The original poster expresses confusion over their calculations and the methods used, indicating a need for clarification on the application of trigonometric functions in this context.

C42711
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[PLAIN]http://img832.imageshack.us/img832/449/physicsu.png
By c42711 at 2011-10-30

I am supposed to find the X and Y components of the above vector. What I tried to do first was dot in a line, forming a triangle. I then tried to find the length of that line using tangent. I got 431.8, but I am not sure that is right. Next, I used the Pythagorean theorem to try to find the X and Y components, I got some crazy numbers, so I know I'm doing something wrong. Any help would be fantastic. Please & thank you.:)
 
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Tangent is not the correct function to use. 147km is the hypotenuse of the triangle.
 
You'd need to use sine for the vertical and cosine for the horizontal. The sine of the angle is y / the hypotenuse, so y = sin71.2 * h. Similarly, x = cos71.2 * h. Hope that helps.
 
So I tried that and got:
Fx= 47.4 km
Fy= 139 km

Does that seem correct?
 
Yeah, those are the correct values.
 
Than you so much, you're the best.:)
 

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