Finding Velocity from Force, Mass and Time

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To find velocity using force, mass, and time, the formula v=at can be applied, where acceleration a is derived from Newton's second law as a=F/m. The discussion centers on whether it's necessary to calculate acceleration separately or if the equation can be rearranged directly to v=Ft/m. Participants argue that both approaches yield the same result algebraically, but there is confusion about the task requirements. Ultimately, the key point is that both methods are mathematically equivalent, despite differing interpretations of the problem's constraints. Understanding the relationship between force, mass, and time is essential for accurately determining velocity.
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Homework Statement


I have been given the force, mass and the time, and I need to find the velocity, and I only have the formula ##v=at##


Homework Equations


##v=at##


The Attempt at a Solution


From the Newton's second law we know that ##a=\frac{F}{m}##,
So Can I just do ##v=\frac{F}{m}t##, or do I need to find acceleration ##a##, then just go with the formula ##v=at##?
 
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-Physician said:

Homework Statement


I have been given the force, mass and the time, and I need to find the velocity, and I only have the formula ##v=at##


Homework Equations


##v=at##


The Attempt at a Solution


From the Newton's second law we know that ##a=\frac{F}{m}##,
So Can I just do ##v=\frac{F}{m}t##, or do I need to find acceleration ##a##, then just go with the formula ##v=at##?

They amount to the same thing.
 
I don't think they amount the same on this task because i only been given the formula ##v=at## so we would define that formula as ##v=\frac{Ft}{m}##.
 
-Physician said:
I don't think they amount the same on this task because i only been given the formula ##v=at## so we would define that formula as ##v=\frac{Ft}{m}##.

Which, again, is the same thing algebraically.
 
Maybe so, but how the task needs it to be, I think it's different
 
I'm not sure what the distinction you're trying to make is.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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