Finding velocity function from a model of force

Click For Summary
SUMMARY

The discussion focuses on deriving the velocity function from a model of force, specifically for a particle experiencing a resistive force of -βv². The initial equation derived is ma = -βv², leading to the separable differential equation dv/dt = -β/m * v². The user initially arrives at an incorrect velocity function, v(t) = m/(β * t) + v₀, but is corrected to the proper form, v(t) = [β/m * t + 1/v₀]⁻¹, which resolves the division by zero issue at t=0.

PREREQUISITES
  • Understanding of Newton's second law of motion (ma = F).
  • Familiarity with separable differential equations.
  • Knowledge of resistive forces in physics.
  • Basic calculus, specifically integration and manipulation of equations.
NEXT STEPS
  • Study the derivation of velocity functions from differential equations in classical mechanics.
  • Learn about resistive forces and their impact on motion in physics.
  • Explore advanced techniques in solving separable differential equations.
  • Review initial conditions and their implications in differential equations.
USEFUL FOR

Students in physics or engineering, particularly those studying dynamics and differential equations, as well as educators seeking to clarify concepts related to motion and resistive forces.

Falken_47
Messages
7
Reaction score
0

Homework Statement



Hi, I've got an assignment which involves finding the function of velocity against time, given the information that the particle is moving with intial velocity of v0 and that it experience a resistive force of -βv2

Homework Equations



From the problem I've derived model of: ma = -βv2

The Attempt at a Solution



re-arranging the model, I have equation of:

dv/dt = -β/m * v2

then, using techniques from seperable equation,

dv/v2 = -β/m * dt

-1/v = -β/m * t + C1

pluging in v(0) = v0

-1/v0 = -β/m * 0 + C1
Or
C1 = -1/v0

Now, plugging in C and rearraging the equation, I obtained

-1/v = -β/m * t - 1/v0

v = m/(β * t) + v0

So as you can see, I'm able to derived the velocity function, but the problem lies to the fact that if I try to plug in t=0 for the velocity, then the function will not work as division by zero is not allowed

Therefore, I'm thinking that something is wrong with my velocity function but up till now I can't still figure it out

Thank you in advance!
 
Physics news on Phys.org
Welcome to PF!

Your calculus is fine, you just forgot how to do division:[tex]\frac{1}{v(t)} = \frac{\beta}{m} t + \frac{1}{v_0}[/tex][tex]\Rightarrow v(t) = \left[ \frac{\beta}{m} t +\frac{1}{v_0} \right]^{-1} \neq \frac{m}{\beta t} + v_0[/tex]
 
Ah yes thank you very much at pointing out my mistake, guess I spend too much time thinking how to actually solve the differential equation that I forgot about that. In any case, thank you for helping me again :)
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 27 ·
Replies
27
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
2
Views
4K
Replies
13
Views
2K