1. The problem statement, all variables and given/known data The position of a particle is given by: x = 2 + 3t - 4t^2. Determine the position of the particle when it changes direction. Determine its velocity when it returns to the position it had at t = 0 sec. x is in met. and t is in sec. 2. Relevant equations I calculated the particle's position by derivating f '(x) = 3t - 4t^2 = 0 3. The attempt at a solution f ' (x) = 3t - 4t^2 = 0 = 3 - 8t t = 0.375 sec. x = 2 + 3(0.375) - 4(0.375)^2 x = 2.5625 met. position My question is: would this be the correct way to find the velocity of the particle(see the problem statement): 3 - 8t = 0 3 - 8(0 sec.) = 3 met/sec. ??