Finding Velocity on a Position/Time Graph

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To find velocity on a position/time graph, it's essential to calculate the slope correctly. The slope represents velocity, and for a straight line, it should remain constant. The formula Vf-Vi/Tf-ti is meant for calculating average velocity, not acceleration. If different calculations yield varying results, it indicates a miscalculation in determining the slope. Ensuring consistent points are used from the graph will help achieve the correct velocity value.
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Hey everyone, I'm having trouble finding velocity on a straight line position/time graph. Every single equation I do ends up with a different answer, which doesn't make sense because it's a straight line.

I know the equation is

Vf-Vi/Tf-ti

The answer to this question is 1.4m/s N

Example:

45-25/28-16= 1.666666m/s Wrong answer. I'm just taking these from the graph by the way.

25-20/16-14= 2.5, completely different answer.

Could someone please explain what I'm doing wrong? I'm calculating the slope which seems to change with every calculation that I do, which I understand is wrong.
 
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Try to post the graph so we can see it. Also, if your v is velocity, you are dividing a velocity change by an elapsed time. That gives acceleration. If you want velocity, divide displacement by time.
 
5pirit said:
Hey everyone, I'm having trouble finding velocity on a straight line position/time graph. Every single equation I do ends up with a different answer, which doesn't make sense because it's a straight line.

I know the equation is

Vf-Vi/Tf-ti

The answer to this question is 1.4m/s N

Example:

45-25/28-16= 1.666666m/s Wrong answer. I'm just taking these from the graph by the way.

25-20/16-14= 2.5, completely different answer.

Could someone please explain what I'm doing wrong? I'm calculating the slope which seems to change with every calculation that I do, which I understand is wrong.
Hello 5pirit. Welcome to PF !

What is the slope of that line?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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