Finding work and velocity through acceleration

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SUMMARY

The discussion focuses on calculating the work done by an applied force on a 1.95 kg particle as it moves along an x-axis from rest, specifically at positions x = 4 m, x = 7 m, and x = 9 m. The relevant equations include F = ma for force and W = integral (F dot dx) for work. The initial attempt to find work involved calculating the area under the acceleration vs. position graph, which was incorrectly interpreted. Clarification was provided regarding the terminology used in the calculations.

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  • Understanding of Newton's second law (F = ma)
  • Knowledge of work-energy principles (W = integral (F dot dx))
  • Familiarity with graph interpretation in physics
  • Basic calculus for integration
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Pudim
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Homework Statement


Figure 7-39 gives the acceleration of a 1.95 kg particle as it is moved from rest along an x-axis by an applied force Fa, from x = 0 to x = 9 m.

Fig. 7-39 : http://www.webassign.net/hrw/W0128-N.jpg

How much work has the force done on the particle when the particle reaches the following points?
(a) x = 4 m
(b) x = 7 m
(c) x = 9 m

What is the particle's speed and direction of travel when it reaches each of the following points?
(a) x = 4 m
(b) x = 7 m
(c) x = 9 m


Homework Equations


F=ma
W=integral (F dot dx)


The Attempt at a Solution


I tried taking the area of the acceleration vs. x graph and timed it by m, which would give me the acceleration of the F vs. x graph, which should be equal to work, but it was incorrect.
I did not know how to find work for the specific position.
 
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Pudim said:
I tried taking the area of the acceleration vs. x graph and timed it
You mean "multiplied it" don't you? "Timed" has a different meaning.

by m,
the mass?

which would give me the acceleration of the F vs. x graph, which should be equal to work, but it was incorrect.
Please show your working and how you know it is wrong.
 

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