Finding Work with constant pressure and temp.

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SUMMARY

The discussion focuses on the thermodynamic calculations for the reaction converting propene (C3H6) to dichloromethane (CH2Cl2) at 298.15 K and one bar pressure. The standard enthalpy change for this reaction is -306.98 kJ mol-1, while the standard enthalpy of formation for CH2Cl2 is -95.52 kJ mol-1. The work done (w) during the reaction is calculated to be 826 J, despite the initial confusion regarding volume change. The relationship between pressure, area, and distance is clarified, emphasizing that work is done when volume changes at constant pressure.

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phizzle86
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The conversion of propene (C3H6) to dichloromethane (CH2Cl2) takes place according to the
reaction
C3H6(g) + 3Cl2(g) 6 3CH2Cl2(g).
At 298.15 K, the standard enthalpy change of this reaction is -306.98 kJ mol-1 and the
standard enthalpy of formation of CH2Cl2(g) is -95.52 kJ mol-1.

Calculate q, w, deltaU, and deltaH for the production of one mole of CH2Cl2(g) by this reaction
at a constant pressure of one bar and a temperature of 298.15 K.



I'm having trouble finding the work done, how can you determine the work done if there's no change in volume? Please help (A: w=826 J)

Thank you.
 
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If the volume changes at constant pressure work is done. Work = pressure X area X distance = pressure X volume
 

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