Is <Z_n\{0},+> a Group Without Zero?

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The discussion centers on whether the set <Z_n\{0},+> qualifies as a group without zero. It is argued that the absence of the identity element, zero, disqualifies it as a group. Additionally, the set fails to meet closure under addition, as the sum of certain elements results in zero, which is not included in the set. Thus, the consensus is that <Z_n\{0},+> cannot be considered a group. The removal of the identity element fundamentally alters the structure required for a group.
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Hi!
Let us say we have a group \langle Z_n \backslash \lbrace 0 \rbrace, \cdot \rangle[\tex] and one element multiplied with another gives kn. n divides kn, so kn equals 0. But we don&#039;t have 0 in the set of the group.<br /> <br /> If the tex stuff didn&#039;t show up, the group should be<br /> &lt;Z_n\{0},+&gt;<br /> <br /> Is this then not a group?<br /> Nille
 
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Originally posted by nille40


Is this then not a group?
Nille

You re damn straight its not a group! a group contains the identity! remove the identity, and you no longer have a group on your hands... but why would you want to go and do something so perverse like remove the identity?
 
Even worse, it's not closed under addition. 1+(-1)=0, which is not an element in the given set.
 
I am studying the mathematical formalism behind non-commutative geometry approach to quantum gravity. I was reading about Hopf algebras and their Drinfeld twist with a specific example of the Moyal-Weyl twist defined as F=exp(-iλ/2θ^(μν)∂_μ⊗∂_ν) where λ is a constant parametar and θ antisymmetric constant tensor. {∂_μ} is the basis of the tangent vector space over the underlying spacetime Now, from my understanding the enveloping algebra which appears in the definition of the Hopf algebra...

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