Finite Reflection Groups in Two Dimensions - R2

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Discussion Overview

The discussion centers around the concept of finite reflection groups in two dimensions, specifically examining the properties of an eigenvector associated with an orthogonal transformation T as described in the text by Grove and Benson. Participants are exploring the implications of the statement regarding the line L being left pointwise fixed by T.

Discussion Character

  • Conceptual clarification
  • Technical explanation

Main Points Raised

  • Peter seeks clarification on why the line L, defined as the set of scalar multiples of the eigenvector x_1, is left pointwise fixed by the transformation T.
  • DonAntonio explains that being an eigenvector with eigenvalue 1 implies that Tx_1 = x_1, suggesting that all vectors in the subspace L are fixed by T.
  • Peter expresses confusion about the term "left" in the context of being pointwise fixed.
  • DonAntonio clarifies that "left" refers to the past participle of "leave," not a directional term.
  • Peter acknowledges a misunderstanding of the text after DonAntonio's clarification.

Areas of Agreement / Disagreement

Participants appear to agree on the meaning of the eigenvector and its implications for the line L being fixed by T, though Peter initially misunderstands the terminology used in the text.

Contextual Notes

Participants reference specific definitions and properties of the transformation T, including its belonging to the group of orthogonal transformations and having a determinant of -1, which may influence the discussion but are not fully explored in detail.

Math Amateur
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I am seeking to understand reflection groups and am reading Grove and Benson: Finite Reflection Groups

On page 6 (see attachment - pages 5 -6 Grove and Benson) we find the following statement:

"It is easy to verify (Exercise 2.1) that the vector x_1 = (cos \ \theta /2, sin \ \theta /2 ) is an eigenvector having eigenvalue 1 for T, so that the line
L = \{ \lambda x_1 : \lambda \in \mathbb{R} \} is left pointwise fixed by T."

I am struggling to se why it follows that L above is left pointwise fixed by T (whatever that means exactly).

Can someone please help - I am hoping to be able to formally and explicitly justify the statement.

The preamble to the above statement is given in the attachment, including the definition of T

Notes (see attachment)

1. T belongs to the group of all orthogonal transformations, O ( \mathbb{R} ).

2. Det T = -1

For other details see attachment

Peter
 

Attachments

Last edited:
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Math Amateur said:
I am seeking to understand reflection groups and am reading Grove and Benson: Finite Reflection Groups

On page 6 (see attachment - pages 5 -6 Grove and Benson) we find the following statement:

"It is easy to verify (Exercise 2.1) that the vector x_1 = (cos \ \theta /2, sin \ \theta /2 ) is an eigenvector having eigenvalue 1 for T, so that the line
L = \{ \lambda x_1 : \lambda \in \mathbb{R} \} is left pointwise fixed by T."

I am struggling to se why it follows that L above is left pointwise fixed by T (whatever that means exactly).

Can someone please help - I am hoping to be able to formally and explicitly justify the statement.

The preamble to the above statement is given in the attachment, including the definition of T

Notes (see attachment)

1. T belongs to the group of all orthogonal transformations, O ( \mathbb{R} ).

2. Det T = -1

For other details see attachment

Peter



"\,x_1 is an eigenvector of \,T with eigenvalue \,1\,\," means \,Tx_1=x_1

To leave a subspace L fixed pointwise means \,\,Tv=v\,,\,\,\forall v\in L

Can you now apply the above to see the statement in that book is trivial?

DonAntonio
 
Thanks for the help - thinking that over

What is meant by (or what is the significance of) 'left' pointwise fixed

Peter
 
Math Amateur said:
Thanks for the help - thinking that over

What is meant by (or what is the significance of) 'left' pointwise fixed

Peter



In this case "left" is the past participle of "leave", and NOT the left of "side", as opposite to "right"...:P)

DonAntonio
 
Oh ... right ... completely misunderstood the text :-(

Thanks

Peter
 

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