First Order Difference Equations

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SUMMARY

The discussion focuses on solving the first order difference equation An+1 = 0.96*An + 2, where A1 = 18, to determine the total amount of water Jill recycles in the first week. The user initially attempts to calculate daily amounts manually, yielding a total of 151.16 litres. However, they seek a more efficient method, exploring the possibility of a formulaic approach similar to those used in arithmetic or geometric sequences. Ultimately, the consensus is that while a formula exists, calculating daily values remains a valid and straightforward solution for this specific problem.

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  • Understanding of first order difference equations
  • Familiarity with geometric progressions
  • Basic algebraic manipulation skills
  • Knowledge of summation techniques
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Students studying mathematics, particularly those focusing on difference equations, algebra, and sequences. This discussion is also beneficial for educators looking to enhance their teaching methods in these areas.

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Homework Statement


Background: Jack's wife Jill, mindful of the water restrictions is determined to carry buckets of bath water out of the house to water bean stalks.

She carries out 18 litres of water on the first day.

The amount of water Jill carries out An, in litres on the nth day is given by the difference equation: An+1=0.96*An+2 , A1=18

Specific: Determine the total amount of water Jill recycles in the first week.

Homework Equations


An+1=0.96*An+2 , A1=18


The Attempt at a Solution


Ok, well I've been working out the answer by finding the total amount recycled each day by manually putting the values into the formula: 1-18 ; 2-19.28 ; 3-20.51 ; 4-21.69 etc and then adding for the total (151.16), but this doesn't seem an efficient way of finding the answer. Is there a formula for the sum (similar to the sums of airthmetic/geometic sequences)?

It is quite possible the answer to this is impossible/obvious, so don't be too harsh :P :)
 
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Have you learned how to solve difference equations? The solution is going to look like A(n)=Crn+D where C and D are constants, so it's the sum of a constant and a geometric progression.
 
Since A_{n+1}= 0.96 A_n+ 2 is a linear equation, we can add solutions to different parts. In particular, we can look for a solution to the equation A_{n+1}= 0.96 a_n first. Since that involves just repeated multiplication, look for a solution of the form A_n= A_1 r^n for some number r. Then A_{n+1}= A_1r^{n+1} and the equation becomes A_1r^{n+1}= 0.96 A_1r^n. Solve that for r.

Now we could probably find a constant that satifies the entire equation, A_{n+1}= .096 A_n+ 2 by just substituting the constant, A, for both A_{n+1} and A_n. Then add the two solutions.

But, frankly, since this only involves a week, just using the difference equation for each day is a perfectly valid way of solving this problem. You don't have to use a shotgun to kill flies!
 
Thanks for the advice chaps! Sounds like I'll just have to suck it up and solve for each day :smile: .
 

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