First order perturbation for hydrogen

[bobred]

Homework Statement

Assume that there is a deviation from Coulomb’s law at very small distances, the Coulomb potential energy between an electron and proton is given by

V_{mod}(r)=\begin{cases}<br /> -\frac{e^{2}}{4\pi\varepsilon_{0}}\frac{b}{r^{2}} &amp; 0&lt;r\leq b\\<br /> -\frac{e^{2}}{4\pi\varepsilon_{0}}\frac{1}{r} &amp; r&gt;b<br /> \end{cases}

(a) Specify the perturbation
(b) Find the first order correction for the ground state
(c) Show that the answer in (b) can be approximated by
E_{1}^{(1)}\approx-\frac{4b^2}{a_0^2}E_R where E_R=\frac{e^{2}}{8\pi\varepsilon_{0}a_0} is the Rydberg energy.

Homework Equations

\psi_0=\frac{2}{a_0^{3/2}}e^{-r/a_0}

E_{1}^{(1)}=\int_{0}^{b}\left| \psi_0 \right|^2 \delta\hat{\textrm{H}} r^2\,\textrm{d}r

b \ll r

The Attempt at a Solution

(a) \delta\hat{\textrm{H}}=-\dfrac{e^{2}}{4\pi\varepsilon_{0}}\left(\dfrac{b}{r^{2}}-\dfrac{1}{r}\right)

so with b \ll r we have e^{-2b/a_0}\approx 1
(b)
E_{1}^{(1)}=\dfrac{e^2 b}{2\pi \varepsilon_{0}a_0^2}

I think the above is correct, I just can't see how to get part (c).

 

[bobred]

Sorry, I was stupid I have it now.

 

[herculed]

Sorry, I was stupid I have it now.

Hi, what had you done wrong initially?

 

[bobred]

I found the first order perturbation which included the exponential terms. To get part c what I should have done was to set the exponential to unity then perform the integration. So part b should have included the exponential terms.
A better way I feel is to note that b/a_0 &lt;&lt;1 then take a 2nd order Taylor series and insert this into the integral in b.