First order perturbation theory problem

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SUMMARY

The discussion centers on calculating the energy shift of a quantum particle in a one-dimensional box under the influence of a linear perturbation potential, v(x) = γx. The wave function for the particle is given by ψ = (√2/L) * sin(nπx/L), where n represents the quantum number. To find the first-order energy shift, one must compute the expectation value of the perturbation using the ground state wave function, specifically for n=1. The key conclusion is that the energy shift is determined by ⟨ψ|v(x)|ψ⟩, where ψ is the ground state wave function.

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Ok so I have a classic particle in a box problem. If a particle in a box, the states of which are given by: ψ = (√2/L) * sin(nπx/L) where n=1,2,3...

is perturbed by a potential v(x) = γx , how do I calculate the energy shift of the ground state in first order perturbation

I'm guessing that the energy shift is given by the expectation value of this perturbation but apart from that I'm stumped.

Thanks in advance guys
 
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hint: you should calculate the expectation of the perturbation with respect to which state?
 

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