1. The problem statement, all variables and given/known data At the aquarium where you work, a fish has gone missing in a 8.00mdeep, 8.80m diameter cylindrical tank. You shine a flashlight in from the top edge of the tank, hoping to see if the missing fish is on the bottom. What’s the smallest angle your flashlight beam can make with the horizontal if it’s to illuminate the bottom? 2. Relevant equations n1sinΘ1 = n2sinΘ2 index of refraction of water: nw = 1.333 index of refraction of air: na = 1.000293 3. The attempt at a solution I thought that the minimum angle would be when the beam hit the edge of the tank and formed a right triangle so the angle in the water would be: Θ2 = arctan(8/8.8) n2 = nw = 1.333 n1 = na = 1.000293 Θ1 = arcsin[(1.333/1.000293)sin(arctan(8/8.8)] = 63.69° So then 1.333sin(42.27°) = 1.000293sin(63.69°) But this is wrong. I also tried to subtract it from 90° but that is wrong as well, to measure from the vertical instead. Thanks in advance.