1. The problem statement, all variables and given/known data At the aquarium where you work, a fish has gone missing in a 10.5m -deep, 9.45m -diameter cylindrical tank. You shine a flashlight in from the top edge of the tank, hoping to see if the missing fish is on the bottom. What’s the smallest angle your flashlight beam can make with the horizontal if it’s to illuminate the bottom? nwater=1.33 (Not sure if this is relevant) 2. Relevant equations tan(θ)=y/x n1sinΘ=n2cosθ 3. The attempt at a solution I first drew a picture of a cylinder with height 10.5 meters and 9.45 meters I assume that in order to illuminate the bottom of the tank, the light needs to hit the side of the tank at half of it's height (if this is incorrect, then I am not sure how to determine where the light hits the side of the tank) At height 10.5/2= 5.25 meters, I solved for Θ; tan(Θ)=5.25/9.45 tan-1(5.25/9.45)= 29.05 degrees I used this equation in snell's law: 1.33sin(29.05)=(1)sin(θair) θ=40.23. I found the θ to the normal, so to find θ to the horizontal: 90-40.23= 49.77 degrees. This answer is incorrect, so any help would be appreciated!