Fnet = ma Ff = -0.3375/0.08 = -4.219N

[CollegeJunior]

Homework Statement

You shoot a 0.08 kg box across the ground with 60 N/m slingshot, stretched back 0.15m. The box slides 4.22m before coming to a stop. What is the force of friction acting on the box as it slides across the ground?

Homework Equations

EPE = 1/2kx^2

The Attempt at a Solution

E1 = 1/2(60)(0.15)^2
E1 = 0.3375J
W = 0 - 0.3375J = -0.3375J

 

[rock.freak667]

The Attempt at a Solution

E1 = 1/2(60)(0.15)^2
E1 = 0.3375J
W = 0 - 0.3375J = -0.3375J

Right so all the work done by the slingshot will be opposided by the work done by the frictional force.

How would you calculate the work done by the friction force F with a distance of 4.22 m ?

 

[CollegeJunior]

Right so all the work done by the slingshot will be opposided by the work done by the frictional force.

How would you calculate the work done by the friction force F with a distance of 4.22 m ?

W = F * D, so F = W / D? I got around -0.08 N for force. Is that the Force of Friction?

 

[haruspex]

E1 = 1/2(60)(0.15)^2
E1 = 0.3375J

You seem to have halved twice over.

 

[CollegeJunior]

You seem to have halved twice over.

?

 

[gneill]

?

Verify your calculation of E1.