Solving for Coefficient of Kinetic Friction in Physics: Fnet=ma

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SUMMARY

The discussion focuses on calculating the coefficient of kinetic friction for a 1000 N crate being pushed across a level floor with a force of 300 N at a 20-degree angle below the horizontal. The kinetic friction formula, Fk = q * Fn, is utilized, where Fn represents the normal force, influenced by both gravitational force and the vertical component of the applied force. Additionally, the discussion addresses the scenario where the force is applied at a 20-degree angle above the horizontal, prompting a query about the crate's acceleration under these conditions.

PREREQUISITES
  • Understanding of Newton's Second Law (Fnet = ma)
  • Knowledge of free-body diagrams
  • Familiarity with the concept of normal force (Fn)
  • Basic principles of kinetic friction (Fk = q * Fn)
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  • Calculate the normal force for different angles of applied force
  • Explore the effects of varying coefficients of friction on motion
  • Learn about the relationship between force, mass, and acceleration in physics
  • Investigate real-world applications of kinetic friction in engineering
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of friction and motion in practical scenarios.

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a 1000-n crate is being held is being pushed across a level floor at a constant speed by a force of f of 300-n at an angle of 20.0 below the horizontal. what is the coefficient kinetic friction between the crate and the floor? if the 300 n force is instead pulling the block at an angle of 20.0 above the horizontal, what will be the acceleration of the crate? assume that the coefficient of riction is the same as in a.

fnet=ma
 
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srry I am really bad at physics ne1 want to help me
 
well, what is kinetic friction? Fk = q*Fn (q = coefficient)

Fn is the force pushing upwards against the block by the floor. in this case it is due to gravity and the downward component of the man's push.

draw a free-body diagram and go from there.
 

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