The problem involves calculating the force of friction acting on a box that is shot across the ground using a slingshot. The box has a mass of 0.08 kg, and the slingshot has a spring constant of 60 N/m, with a stretch of 0.15 m. The box slides a distance of 4.22 m before stopping.
The discussion is ongoing, with participants verifying calculations and questioning the methodology used in determining the work done by the slingshot and the frictional force. There is no explicit consensus yet, as participants are exploring different interpretations and calculations.
Some participants note potential errors in calculations, specifically regarding the elastic potential energy and its application in the context of work done by friction. There is an emphasis on ensuring accurate calculations before proceeding.
CollegeJunior said:The Attempt at a Solution
E1 = 1/2(60)(0.15)^2
E1 = 0.3375J
W = 0 - 0.3375J = -0.3375J
rock.freak667 said:Right so all the work done by the slingshot will be opposided by the work done by the frictional force.
How would you calculate the work done by the friction force F with a distance of 4.22 m ?
You seem to have halved twice over.CollegeJunior said:E1 = 1/2(60)(0.15)^2
E1 = 0.3375J
haruspex said:You seem to have halved twice over.
CollegeJunior said:?