Focal length of plano convex lens

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The discussion focuses on calculating the focal length of a plano-convex lens with a diameter of 6 cm and a center thickness of 3 mm. The user applies the lensmaker's formula, determining the radius of curvature (R) to be 15 cm and subsequently calculating the focal length (f) as 30 cm. Another participant confirms the calculation and clarifies that the lensmaker's formula is being used correctly, distinguishing it from the thin lens equation. The exchange emphasizes the importance of understanding the appropriate formulas for lens calculations. The focal length derived is validated as accurate.
Amith2006
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# Diameter of a Plano-convex lens is 6 cm and the thickness at the center is 3 mm. If the speed of light in the material of the lens is 2 x 10^8 m/sec, what is the focal length of the lens?
I solved it in the following way:
Let R be the radius of curvature of the convex surface.
Given that AB = 3 mm = 0.3 cm, AD = CD/2 = 3 cm, refractive index(n) = 1.5
By the property of circles,
AB = (AD^2)/(2R)
Therefore, R = (AD^2)/(2AB)
= 9/(2 x 0.3)
= 15 cm
According to thin lens formula,
1/f = (n – 1)/R
Solving I get,
f = 30 cm
Is it right?
 

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Amith2006 said:
# Diameter of a Plano-convex lens is 6 cm and the thickness at the center is 3 mm. If the speed of light in the material of the lens is 2 x 10^8 m/sec, what is the focal length of the lens?
I solved it in the following way:
Let R be the radius of curvature of the convex surface.
Given that AB = 3 mm = 0.3 cm, AD = CD/2 = 3 cm, refractive index(n) = 1.5
By the property of circles,
AB = (AD^2)/(2R)
Therefore, R = (AD^2)/(2AB)
= 9/(2 x 0.3)
= 15 cm
According to thin lens formula,
1/f = (n – 1)/R
Solving I get,
f = 30 cm
Is it right?
Yes. For the benefit of others, you are using the lensmaker's forumula for thin lenses, not to be confused with the thin lens equation.

AM
 
Thanks for your help.
 

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